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|Section2= |Section3= }} Tin(IV) bromide is the chemical compound SnBr4. It is a colourless low melting solid.〔 SnBr4 can be prepared by reaction of the elements at normal temperatures:〔Egon Wiberg, Arnold Frederick Holleman (2001) ''Inorganic Chemistry'', Elsevier ISBN 0-12-352651-5〕 :Sn + 2Br2 → SnBr4 In aqueous solution Sn(H2O)64+ is the principal ionic species amongst a range of 6 coordinate ions with from 0-6 bromide ligands (e.g. Sn(H2O)64+, SnBr(H2O)53+)〔Sn NMR and vibrational spectroscopy, Taylor M. J. ; Coddington J. M., Polyhedron 1992, 11, 12, 1531-1544, 〕 In basic solution the Sn(OH)62− ion is present.〔 SnBr4 forms 1:1 and 1:2 complexes with ligands, e.g. with trimethylphosphine the following can be produced, SnBr4.P(CH3)3 and SnBr4.2P(CH3)3.〔Preparation, Infrared and Raman Spectra, and Stereochemistries of Pentacoordinate Trimethylphosphine Complexes, MX4•P(CH3)3 and MX4•P(CD3)3 where M = Ge or Sn and X = Cl or Br, Frieson D. K., Ozin G. A., Can. J. Chem. 51(16): 2697–2709 (1973) 〕 SnBr4 crystallises in a monoclinic form with molecular SnBr4 units that have distorted tetrahedral geometry.〔Die Kristallstruktur von SnBr4 , Brand P., Sackmann H., Acta Crystallographica ( 1963), 16, 446-451, 〕 ==References== 抄文引用元・出典: フリー百科事典『 ウィキペディア（Wikipedia）』 ■ウィキペディアで「Tin(IV) bromide」の詳細全文を読む スポンサード リンク
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